 PAT(A) 1133. Splitting A Linked List (25)

1133. Splitting A Linked List (25)

Given a singly linked list, you are supposed to rearrange its elements so that all the negative values appear before all of the non-negatives, and all the values in [0, K] appear before all those greater than K. The order of the elements inside each class must not be changed. For example, given the list being 18→7→-4→0→5→-6→10→11→-2 and K being 10, you must output -4→-6→-2→7→0→5→10→18→11. Input Specification:

Each input file contains one test case. For each case, the first line contains the address of the first node, a positive N (<= 105) which is the total number of nodes, and a positive K (<=1000). The address of a node is a 5-digit nonnegative integer, and NULL is represented by -1.

Then N lines follow, each describes a node in the format:

where Address is the position of the node, Data is an integer in [-105, 105], and Next is the position of the next node. It is guaranteed that the list is not empty.

Output Specification:

For each case, output in order (from beginning to the end of the list) the resulting linked list. Each node occupies a line, and is printed in the same format as in the input.

Sample Input: 00100 9 10 23333 10 27777 00000 0 99999 00100 18 12309 68237 -6 23333 33218 -4 00000 48652 -2 -1 99999 5 68237 27777 11 48652 12309 7 33218 Sample Output: 33218 -4 68237 68237 -6 48652 48652 -2 12309 12309 7 00000 00000 0 99999 99999 5 23333 23333 10 00100 00100 18 27777 27777 11 -1

代码

/*
* Problem: 1133. Splitting A Linked List (25)
* Author: HQ
* Time: 2018-03-13
* State: Done
* Memo: 链表
*/
#include "iostream"
#include "vector"
using namespace std;

struct Node {
int data;
int next;
};

int N,K;
int start;

int main() {
scanf("%d %d %d", &start, &N, &K);
int x;
for (int i = 0; i < N; i++) {
scanf("%d %d %d", &add, &x, &next);
struct Node temp = { x,next };
}
bool first = true;
int s = start;
while (s != -1) {
if (addrs[s].data < 0) {
if (first)
first = false;
else
printf(" %05d\n", s);
printf("%05d %d", s, addrs[s].data);
}
}
s = start;
while (s != -1) {
if (addrs[s].data >= 0 && addrs[s].data <= K) {
if (first)
first = false;
else
printf(" %05d\n", s);
printf("%05d %d", s, addrs[s].data);
}
}
s = start;
while (s != -1) {
if (addrs[s].data > K) {
if (first)
first = false;
else
printf(" %05d\n", s);
printf("%05d %d", s, addrs[s].data);
}
}
cout << " -1"<< endl;
system("pause");
}